Looking to create a straightforward menu bar using the ul tag with 4 links. The ul spans 100% of the screen width, so each li element should be 25%.
I attempted to implement this, but the final list item ends up dropping to the next line. However, setting the width to 23% for each li fixes the issue. I wonder why 25% isn't sufficient?
Here is the link to my pen:
http://codepen.io/anon/pen/XKryKW Any assistance would be greatly appreciated! Thank you.
Your HTML code is causing spacing issues with inline block elements. Removing the spaces should solve the problem. For more information, you can refer to this explanation: https://css-tricks.com/fighting-the-space-between-inline-block-elements/
You can view an example at: http://codepen.io/ruchiccio/pen/YWKRVQ
<ul>
<li><a> first</a></li><li><a> second</a></li><li><a> third</a></li><li><a> fourth</a></li>
</ul>
When using display: inline-block, there will always be a gap between blocks due to the default behavior. Additionally, adding 22px padding increases the total width beyond 100%. To resolve this issue, include box-sizing: border-box; in your CSS.
li {
font-size:25px;
padding: 22px;
width:25%;
text-align:center;
float: left;
display: block;
box-sizing: border-box;
}`
To start, the first step is to eliminate the padding on the right and left of the lis. Additionally, you should also include font-size:0 in the ul to prevent spacing between the lis.
*{
margin:0;
padding:0;
}
ul
{
height:70px;
background-color:#e1973d;
list-style-type:none;
width:100%;
font-size:0;
}
li
{
font-size:25px;
padding: 22px 0;
width:25%;
text-align:center;
display:inline-block
}<ul>
<li><a> first</a> </li>
<li><a> second</a> </li>
<li><a> third</a> </li>
<li><a> fourth</a> </li>
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