Display an image when the link is hovered over within a table

I'm looking for a way to display a scanned receipt image when hovering over a link within a table. I've written some code but it's not working as expected. Can anyone help me figure out what's wrong?

Here is the current state of my code:

CODE

 jQuery(document).ready(function() {
   $(".preview").hover(function() {
     $(this).closest('img').show();
   }, function() {
     $(this).closest('img').hide();
   });
 });
 .hide-image {
   display: none;
 }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<tr>
  <td>01/14/16</td>
  <td>
    <a href="#" class="preview">Lowes Receipt
          <img src="image-path/image.jpg" class="hide-image" style="z-index: 100; position: absolute;" /></a>
  </td>
  <td>$1235.96</td>
</tr>

javascriptjqueryhtmlcss

Answer №1

Is there a better way to accomplish this task without relying solely on CSS?

.hide-image {
  display: none;
  z-index: 100;
  position: absolute;
}
.preview:hover .hide-image {
  display: block
}
<tr>
  <td>01/14/16</td>
  <td>
    <a href="#" class="preview">Lowes Receipt
      <img src="//lorempixel.com/100/100" class="hide-image" /></a>
  </td>
  <td>$1235.96</td>
</tr>

Answer №2

$(document).ready(function() {
          $(".preview").hover(function() {
            $(this).find('img').fadeIn();
          }, function() {
            $(this).find('img').fadeOut();
          });
        });
.hide-image {
          display: none;
        }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<tr>
  <td>01/14/16</td>
  <td>
    <a href="#" class="preview">Lowes Receipt
    <img src="https://via.placeholder.com/100" class="hide-image" style="z-index: 100; position: absolute;" />
    </a>
  </td>
  <td>$1235.96</td>
</tr>

Feel free to give this approach a try.

Answer №3

Consider using the next() method:

$(this).next('img').show();

Alternatively, you can use find() method:

$(this).find('img').show();

Answer №4

Moving up the DOM is key. I've learned from my past mistakes. Try using find("img");

Check out this demo: https://jsfiddle.net/unix102/yspbrwkd/

$(document).ready(function () {
    $(".preview").hover(function(){
        $(this).find('img').fadeIn();
     }, function(){
        $(this).find('img').fadeOut();
    });
});

Answer №5

The issue appears to be related to the functionality of jQuery's .show() method.

When using this method, the selected elements are instantly made visible without any animation. It is similar to setting .css( "display", "block"), but it also restores the original display property value.

Because the default display property value is set to none, calling show() has no effect.

Here's an alternative approach with jQuery while improving coding practices by moving some inline styles to a separate CSS file:

HTML

<tr>
   <td>01/14/16</td>
   <td>
      <a href="#" class="preview">Lowes Receipt
      <img src="image-path/image.jpg" class="receipt-image" /></a>
   </td>
   <td>$1235.96</td>
</tr>

CSS

.receipt-image {
    display: none;
    position: absolute;
    z-index: 100; 
}
.receipt-image.visible { 
    display: block;
}

Javascript

jQuery(document).ready(function () {
    $(".preview").hover(function(){
        $(this).closest('.receipt-image').addClass('visible');
    }, function(){
        $(this).closest('.receipt-image').removeClass('visible');
    });
});

However, achieving the same result solely with CSS is possible too, eliminating the need for jQuery or JavaScript! Remove the JS code and try out this CSS solution:

CSS

.receipt-image {
    display: none;
    position: absolute;
    z-index: 100; 
}
.preview:hover .receipt-image { 
    display: block;
}

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