Here are the list items:
<ul>
<li>...</li>
<li>...</li>
<li>...</li>
<li>...</li>
<li>...</li>
<li>...</li>
<li>...</li>
<li>...</li>
<li>...</li>
</ul>
Is there a way to extract the second half of this list and place it before the first <li> item?
const unorderedList = $('ul');
const listItems = unorderedList.children('li');
unorderedList.prepend(listItems.slice(Math.round(listItems.length / 2)))
Example: http://jsfiddle.net/8SNGn/
This script first saves the reference to the <ul> element and its child <li> elements using the children()[docs] method.
Then it utilizes the prepend()[docs] method to insert the last li elements at the beginning of the ul.
To select the last half of elements, it divides the total number of li elements in two (rounding up with Math.round() for odd numbers) using the slice()[docs] method.
EDIT:
I noticed that your question contains the term "clone".
Although not explicitly stated, if you wish to clone the last half instead, you can achieve this by utilizing the clone()[docs] method.
const unorderedList = $('ul');
const listItems = unorderedList.find('li');
unorderedList.prepend(listItems.slice(Math.round(listItems.length / 2)).clone())
Example: http://jsfiddle.net/8SNGn/1/
If you prefer rounding down instead, you can substitute Math.floor() for Math.round.
let elements = $("ul li");
elements.filter(function(position) {
return position >= elements.length / 2;
}).prependTo($("ul")[0]);
This code snippet is expected to function correctly.
let totalItems = $('li').length - 1;
for(let j = 0; j < totalItems/2; j++){
let $listItem = $('li').eq(totalItems);
$('ul').prepend($listItem);
}
See it in action here: http://jsfiddle.net/CreativeCoder123/Qw3XY/
Implementing jquery prepend function can be done by visiting this link
Check out the filter function .slice() in jQuery:
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