Concealing a Div on Click Outside of Child Div in ReactJS

Question

Concealing a Div on Click Outside of Child Div in ReactJS

I have a parent div with a child div in the center. I am trying to figure out how to close the parent div only when clicking outside of the child div. My current code is structured like this, using triggerParentUpdate to control whether the div should be displayed or not.

<div onClick={this.props.triggerParentUpdate} className="signupModalContainer">
    <div className="embed-responsive embed-responsive-16by9">
        <form action="action_page.php">
            <div className="container">
                <button onClick={this.props.triggerParentUpdate} type="button" className="closebtn">X</button>
            </div>
        </form>
    </div>
</div>

The onclick function in the parent div (className="signupModalContainer") currently closes all the divs when clicked, including the child divs. If I remove this function, only the close button can close the divs.

Any suggestions on how to achieve the desired functionality are appreciated. Thank you!

javascript html css reactjs

Answer 1

Answer №1

Implement a handler for the child div's onClick event listener, specifically designed to prevent the event from bubbling up to the parent element.

For more detailed information, you can visit Event.stopPropagation.

class SomeComponent extends Component {
  handleCloseButton = e => {
    // Use this method to stop the event from propagating upwards.
    // This way, the parent div's "onClick" event will not be triggered.
    e.stopPropagation();
    this.props.triggerParentUpdate(e);
  }

  render () {
    // ...
    return (
      <div onClick={this.props.triggerParentUpdate} className="signupModalContainer">
          <div className="embed-responsive embed-responsive-16by9">
              <form action="action_page.php">
                  <div className="container">
                  <button onClick={this.handleCloseButton} type="button" className="closebtn">X</button>                             
                  </div>
              </form> 
          </div>
      </div>
    );
  }
)

Answer 2

Implement a handler for the child div's onClick event listener, specifically designed to prevent the event from bubbling up to the parent element.

For more detailed information, you can visit Event.stopPropagation.

class SomeComponent extends Component {
  handleCloseButton = e => {
    // Use this method to stop the event from propagating upwards.
    // This way, the parent div's "onClick" event will not be triggered.
    e.stopPropagation();
    this.props.triggerParentUpdate(e);
  }

  render () {
    // ...
    return (
      <div onClick={this.props.triggerParentUpdate} className="signupModalContainer">
          <div className="embed-responsive embed-responsive-16by9">
              <form action="action_page.php">
                  <div className="container">
                  <button onClick={this.handleCloseButton} type="button" className="closebtn">X</button>                             
                  </div>
              </form> 
          </div>
      </div>
    );
  }
)

Answer 3

Answer №2

Detecting clicks in the parent element is a simple task

   const checkParentClick = event => {
    event.preventDefault();

    if (event.target === event.currentTarget) {
      console.log('parent clicked');
      // 👇 add your custom logic here
    }
  };

Answer 4

Detecting clicks in the parent element is a simple task

   const checkParentClick = event => {
    event.preventDefault();

    if (event.target === event.currentTarget) {
      console.log('parent clicked');
      // 👇 add your custom logic here
    }
  };

Concealing a Div on Click Outside of Child Div in ReactJS

Answer №1

Answer №2

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