Change the background color of form checkboxes in a different way

I'm currently working on a form design and I would like to create a feature where the background color of each option alternates. This is similar to how you can style alternating rows in tables using CSS

tr:nth-child(even){background-color: #f2f2f2;}

In my attempts to achieve this effect, I experimented with using unique IDs that were linked to different CSS styles for displaying various background colors:

function options(){
        var i =0;
        var name;
        $(xmlDoc).children().children().each(function(){
            name = $(this).children().first().text();
            if(i % 2 == 0){
                $('form').append(" <input type='checkbox' id=odd'" + "value=" + name + ">"+ name + "<br>");
            }
            else{
                $('form').append(" <input type='checkbox' id='even'" + "value=" + name + ">"+ name + "<br>");
            }
            i++;
        });
    }

However, I discovered that the background color can only be changed within the form itself. Is there an alternative method to accomplish this desired effect?

Answer №1

Have you experimented with the following CSS code:

input[type="checkbox"]:nth-of-type(2n-1) {
background-color: #222222;
}

input[type="checkbox"]:nth-of-type(2n) {
background-color: #f2f2f2;
}

Answer №2

To modify the form's color, you need to access it directly from the form element.

<form style="background-color: #E0FFFF"></form>

Unfortunately, there isn't a way to target specific input elements for styling individually. However, a workaround I discovered is to convert the entire form into a list and then apply styles using CSS.

li:nth-child(even) {background-color: #f2f2f2;}

Here is an example of how the HTML structure would look:

<ul style='list-style-type: none;'><li><input type='checkbox' id='name' value='name'>name<br></li></ul>

The ul element's styling is used to remove bullet points from the list.

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