Attempting to achieve the effect where the entire row of a table changes color when the mouse hovers

I'm attempting to create a gradient effect for an entire row in a table when the mouse hovers over any cell within that row. Despite using what I believe is the correct CSS code, nothing changes upon mouseover (even though the original gradient appears fine). Below is the CSS I am currently using:

td {
  font-family: 'Roboto Slab', serif;
  font-size: 18px;
  padding: 3px 15px;
  text-align: center;
}

.silvergrad {
  filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#FFF', endColorstr='#CCC');
  background: -webkit-gradient(linear, left top, left bottom, from(#FFF), to(#CCC));
  background: -moz-linear-gradient(top, #FFF, #CCC);
}

.silvergrad tr:hover td {
  filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#999', endColorstr='#CCC');
  background: -webkit-gradient(linear, left top, left bottom, from(#999), to(#CCC));
  background: -moz-linear-gradient(top, #999, #CCC);
}

I have experimented with and without the "td" selector after ".silvergrad tr:hover". Here is the HTML code for the row in question:

<tr class="silvergrad">
  <td>Some stuff</td>
  <td>Some stuff</td>
  <td>Some stuff</td>
</tr>

If anyone can spot where I may be going wrong, I would greatly appreciate it. Thank you in advance.

csshover

Answer №1

Make a simple adjustment to one of your CSS rules:

.silvergrad tr:hover td {

Change it to:

.silvergrad:hover td {

View the jsFiddle example

In this scenario, there is no tr element that is a child of .silvergrad. Actually, silvergrad itself represents the tr.

Answer №2

Instead of specifying the table row as a descendant of an element with the silvergrad class, remember that the table row is the element with the silvergrad class. Use this code snippet for proper styling:

tr.silvergrad:hover td {
  filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#999', endColorstr='#CCC');
  background: -webkit-gradient(linear, left top, left bottom, from(#999), to(#CCC));
  background: -moz-linear-gradient(top, #999, #CCC);
}

Answer №3

The CSS is targeting a tr element that is within an element containing the class .silvergrad, instead of one that directly has it. To adjust, consider using this code:

tr.silvergrad:hover>td

Answer №4

Perhaps there is a transformation happening behind the scenes.

Give this gradient code a shot:

.silvergrad tr:hover>td{
    background-color: #999;
    background-image: -moz-linear-gradient(top, #999, #ccc);
    background-image: -webkit-gradient(linear, 0 0, 0 100%, from(#999), to(#ccc));
    background-image: -webkit-linear-gradient(top, #999, #ccc);
    background-image: -o-linear-gradient(top, #999, #ccc);
    background-image: linear-gradient(to bottom, #999, #ccc);
    background-repeat: repeat-x;
    filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#ff999',endColorstr='#ffccc', GradientType=0);
}

Let me know your thoughts after giving it a try :)

Answer №5

Finally, success! It's funny because I could have sworn I already tried this particular solution among the many others I attempted. The only change I made was:

.silvergrad tr:hover td {

to just

.silvergrad:hover {

and voilà, it now works like a charm. Many thanks to everyone who provided such quick responses.

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