Is there a way to change the background color of an ion-item when it is clicked by a user? Any help on how to achieve this would be greatly appreciated.
Here's an example code snippet:
<ion-item (click)="openDetail(variant)">{{variant.ProductVariantName}
<ion-button slot="end" [hidden]="variant.ProductVariantValue.length==0" fill="clear" color="dark">
<i [class]="variant.showDetail ? 'fa fa-arrow-up fa-lg':'fa fa arrow down fa-lg'"></i>
</ion-button>
</ion-item>
Make sure to check out the official documentation for more information (specifically under "using Css" or "javascript") : https://ionicframework.com/docs/theming/css-variables#ionic-variables
If you want to customize the appearance, consider modifying this variable in your theming (or custom css)
--background-activated : Background of the button when activated
For example :
.fancy-button {
--background-activated: red;
}
In terms of changing the color only, I suggest sticking with Ionic's solutions rather than complicating things with an angular approach. Keep it simple and efficient for better performance. However, if you need to apply multiple classes after clicking a component, then [ngClass] can be useful.
To start, within your component.ts document:
Begin by declaring a new variable:
buttonColor: string = '#000';
Next, make adjustments to your HTML as shown below:
<ion-item (click)="openDetail(variant)" [ngStyle]="{'background-color':
buttonColor}">{{variant.ProductVariantName}
<ion-button slot="end" [hidden]="variant.ProductVariantValue.length==0"
fill="clear" color="dark">
<i [class]="variant.showDetail ? 'fa fa-arrow-up fa-lg':'fa fa arrow down
fa-lg'"></i>
</ion-button>
</ion-item>
Finally, within your function implement the following changes:
openDetail(variant){
this.buttonColor = '#345465';
}
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